16x^2-16x+4-4(4x-2)+3=0

Solution for 16x^2-16x+4-4(4x-2)+3=0 equation:

16x^2-16x+4-4(4x-2)+3=0

We add all the numbers together, and all the variables

16x^2-16x-4(4x-2)+7=0

We multiply parentheses

16x^2-16x-16x+8+7=0

We add all the numbers together, and all the variables

16x^2-32x+15=0

a = 16; b = -32; c = +15;
Δ = b2-4ac
Δ = -322-4·16·15
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-8}{2*16}=\frac{24}{32}
=3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+8}{2*16}=\frac{40}{32}
=1+1/4
$